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Is there any example of linear operator which is bounded on all Besov spaces but not on Trie...

Turns out it was not known. So I took a week and write it down. You can see in the arXiv for a complete proof. For convenience let $n=1$. Let $(\phi_j)_{j=0}^\infty$ be the family of Schwartz function …
Liding Yao's user avatar