Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with gn.general-topology
Search options not deleted
user 117164
Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.
1
vote
Miscenko example of linearly Lindelof non Lindelof is not normal
I think I figured that out.
Assume $U$ and $V$ are open in $M$ and $H \subseteq V$ and $K \subseteq U$, such that $U \cap V = \emptyset$.
Lemma: There are $\{D_n : n >0\}$ such that $D_n \subseteq U …
- 11