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Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.
2
votes
1
answer
171
views
How can one test whether a given analytic curve in the plane is algebraic or not?
Suppose $\Gamma$ is an analytic Jordan curve in the complex plane $\mathbb{C}$. What are ways to test whether $\Gamma$ is (contained in) an algebraic curve, i.e., whether there exists a real polynomia …
2
votes
0
answers
79
views
On the (Brouwer-Koebe) Continuity Method
The so-called Continuity Method is a simple yet powerful method to show that a given continuous injective map is surjective. Namely, suppose that $f:X \to Y$ is a map between two connected manifolds $ …
9
votes
3
answers
717
views
Can the limit set of an infinitely generated Schottky group have positive area?
Dear Mathoverflow Community,
Suppose that $\Omega$ is a domain in the Riemann Sphere $\widehat{\mathbb{C}}$ with $\infty \in \Omega$, and assume that every connected component of $\partial \Omega$ is …
13
votes
3
answers
713
views
How bad can a circle domain get?
Let $X$ be a domain in the Riemann sphere $\widehat{\mathbb{C}}$. We say that $X$ is a circle domain if every connected component of its boundary is either a circle or a point.
It was conjectured by …
14
votes
4
answers
3k
views
A learning roadmap to the Schramm-Loewner evolution (SLE) for the complex analyst
I would like some good references to learn about the Schramm-Loewner evolution (SLE), for a complex analyst with no background in probability.
A quick google search gave a lot of references on SLE th …
10
votes
1
answer
372
views
On the conformal removability of Jordan curves
We say that a compact subset $E$ of the Riemann sphere $\mathbb{C}_\infty$ is (conformally) removable if every homeomorphism of $\mathbb{C}_\infty$ conformal outside $E$ is actually conformal everywhe …
1
vote
1
answer
142
views
On the geometry of roots of a sum of complex linear fractions
I was wondering if there is anything known about the geometry (position) of the roots of a rational map of the form
$$R(z):= \sum_{j=1}^{n} \frac{a_j}{z-p_j},$$
where the $a_j$'s are nonzero complex n …
9
votes
1
answer
868
views
The Riemann mapping theorem via extremal problems
Let $X \subsetneq \mathbb{C}$ be a simply connected domain. The Riemann mapping theorem states that there exists a biholomorphism of $X$ onto the unit disk $\mathbb{D}$. A simple and elegant way to ob …
2
votes
2
answers
2k
views
On the existence of a holomorphic logarithm
Hi,
The following is probably well-known, but I couldn't find anything in the literature. Any reference would be nice.
Let $\Omega$ be a domain in the complex plane, and let $f$ be holomorphic and o …
2
votes
2
answers
367
views
On the set of zero radial limits of bounded analytic functions
Hi,
Let $f$ be a non-identically zero bounded analytic function in the open unit disk $\mathbb{D}$. It is well-known that $f$ has radial limits almost everywhere on the unit circle $\mathbb{T}$. Let …
16
votes
2
answers
2k
views
On the Universality of the Riemann zeta-function
Hi,
I have a question regarding the universality property of the Riemann zeta-function. I am no expert on this, so I'd be glad for any relevant reference.
First, recall Voronin's remarkable theorem …
6
votes
1
answer
1k
views
On holomorphic branched coverings of a domain in the plane to the unit disk
This question is partly motivated by my answer to this question on math.stackexchange.
Let $\Omega$ be a bounded $n$-connected domain in the plane, bounded by $n$ pairwise disjoint Jordan curves.
I …
6
votes
0
answers
290
views
What is the status of the subadditivity problem for analytic capacity?
Hi,
Here is another question that concerns analytic capacity. For a compact set $K$ in the plane, define the analytic capacity of $K$ by
$$\gamma(K):=\sup|f'(\infty)|,$$
where the supremum is taken o …
23
votes
0
answers
1k
views
Is analytic capacity inner regular?
For a compact set $K$ in the complex plane, define the analytic capacity of $K$ by
$$\gamma(K) := \sup |f'(\infty)|$$
where the supremum is taken over all functions $f$ holomorphic and bounded by $1$ …
4
votes
1
answer
457
views
Bounded spherical derivative implies finite order
Hi,
Let $f$ be an entire function. The spherical derivative $\rho(f)$ is defined by
$$\rho(f)(z):= \frac{|f'(z)|}{1+|f(z)|^2}.$$
A result from Clunie and Hayman states that if $\rho(f)$ is bounded, …