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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

24 votes

Simplest examples of rings that are not isomorphic to their opposites

To amplify on Bugs Bunny's answer: let $D$ be a finite dimensional central division algebra over a field $K$. Then $D \otimes_K D^{\operatorname{op}} \cong \operatorname{End}_K(D)$. From this it fol …
Pete L. Clark's user avatar
6 votes

Is there an algebraic proof of the infinitude of primes?

[I don't really know what constitutes an "algebraic proof" of infinitude of prime numbers.] The proof that BCnrd alludes to above is described in somewhat more length on p. 5 of http://alpha.math.uga. …
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18 votes
Accepted

Which commutative groups are the group of units of some field?

The following paper claims an answer to this question: Dicker, R. M. A set of independent axioms for a field and a condition for a group to be the multiplicative group of a field. Proc. London Math. …
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10 votes
Accepted

notation for formal Laurent series

I agree with the mathematician of your acquaintance -- well, okay, I am the mathematician of your acquaintance. Here are some references for the notation $K((x))$ for the field of formal Laurent seri …
Pete L. Clark's user avatar
6 votes

Infinite dimensional central simple algebras

I only know a little bit about this, so for your sake I hope someone more knowledgeable comes along... As for your first question: It is not hard to see that the tensor product of any two central simp …
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15 votes

transcendental Galois theory

Even in our day of sophisticated search engines, it still seems that the success of a search often turns on knowing exactly the right keyword. I just followed up on Sylvain Bonnot's comment above. T …
Pete L. Clark's user avatar
12 votes

What makes a theorem *a* "nullstellensatz."

For a field $k$, by a "Nullstellensatz" over $k$, I mean an explicit description of the Galois connection between subsets of $k^n$ and ideals in the polynomial ring $k[x_1,\ldots,x_n]$. See this MO q …
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7 votes

$n$-forms representing zero (versus division rings)

You are asking about a venerable and active area in Diophantine equations lying at the border of arithmetic geometry and analytic number theory. Some keywords are forms in many variables and circle m …
Pete L. Clark's user avatar
3 votes
Accepted

Alternative algebras in characteristic 2, especially scalar extension

A good samaritan has delivered an answer directly to my email account. It is indeed almost obvious, as long as one ignores the bit about the multiplication operators! Take for instance the left alte …
Pete L. Clark's user avatar
8 votes

Rings with right inverses

For a memorable explicit example, let $V = \mathbb{R}[x]$ be the real vector space of polynomial functions, and let $R = \operatorname{End}(V)$ be the ring of $\mathbb{R}$-linear endomorphisms (aka li …
Pete L. Clark's user avatar
11 votes

Indeterminate "$x$" in algebra/ring Theory

Among infinitely many other places, this issue is discussed in Sections 4.3 and 4.4 of my notes on commutative algebra: http://alpha.math.uga.edu/~pete/integral.pdf In Section 4.3 I give Mariano's def …
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9 votes

Expressing $-\operatorname{adj}(A)$ as a polynomial in $A$?

As an arithmetic geometer, I have no choice but to use topological methods hand in hand with algebraic methods. Very likely necessity has been the mother of aesthetics here, but I find proofs of line …
Pete L. Clark's user avatar
9 votes

What does the semiring of ideals of a ring R tell us about R?

This is sort of a sideways answer, but: in many ways the monoid $\operatorname{Prin}(R)$ of principal ideals carries more information. If $R$ is a domain $\operatorname{Prin}(R)$ is a cancellative mo …
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50 votes
Accepted

"Algebraic" topologies like the Zariski topology?

Yes, there are plenty of such things. [In the following, "compact" implies "locally compact" implies "Hausdorff".] 1) To a Boolean algebra, one associates its Stone space, a compact totally discon …
Pete L. Clark's user avatar
6 votes

Which R-algebras are the group ring of some group over a ring R?

Reid Barton's very nice answer to Computing the structure of the group completion of an abelian monoid, how hard can it be? contained a pointer to the wikipedia page for the Eilenberg-Mazur swindle. …
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