Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 11260
2 votes

Express as Meijer-G function

start from the identity $$G^{2,0}_{0,2}(z,\tfrac{1}{2}|b,c)=2z^{b+c}K_{c-b}(2z),$$ substitute $b=0$ and $c=1/2$, $$G^{2,0}_{0,2}(z,\tfrac{1}{2}|0,\tfrac{1}{2})=2z^{1/2}K_{1/2}(2z)=\sqrt{\pi}e^{-2z},$$ …
Carlo Beenakker's user avatar
4 votes
Accepted

What is exponentially fitted osculating straight line?

it's jargon for a function of the form $$y(x)=e^{a(x-x_0)}[b(x-x_0)+c]$$ where the constants $a,b,c$ are determined such that $y(x)$ osculates the function $f(x)$ you are fitting to at $x=x_0$: $$y(x …
Carlo Beenakker's user avatar