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17 votes

Operator norm of square root of matrix vs original

This is not true. For example, if $$ A = \frac{2}{1 + \sqrt{5}}\begin{bmatrix} 1 & 1 \\ 0 & 1\end{bmatrix} $$ then $\|A\| = 1$. Furthermore, $A$ has exactly $2$ square roots, which are $$ B_{\pm} = …
Nathaniel Johnston's user avatar
11 votes
Accepted

Equivalence of entrywise 1-norm and Schatten-1 norm

The best such inequality that depends only on $m$ and $n$ is: $$ \frac{1}{\sqrt{mn}}\|A\| \leq \|A\|_* \leq \|A\| $$ The right inequality is tight when $A$ is a matrix with a $1$ in the top-left corne …
Nathaniel Johnston's user avatar
5 votes

When does a finite metric induce a matrix norm?

Not a complete answer, but a sufficient condition. The equation $(e_i - e_j)^TQ(e_i - e_j) = d(i,j)^2$ tells us that $q_{i,i} + q_{j,j} - 2q_{i,j} = d(i,j)^2$, so $q_{i,j} = (q_{i,i} + q_{j,j} - d(i,j …
Nathaniel Johnston's user avatar