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Theory and applications of Lévy processes (stochastic processes with stationary and independent increments): e.g. path properties, stochastic differential equations driven by jump-type processes, fluctuation theory of Lévy processes, queuing theory.

2 votes
Accepted

Existence of unique convolution semigroups of probability measures on more general spaces th...

A quick Google search on "infinitely divisible" and "Banach space" leads to Linde's Probability in Banach Spaces: Stable and Infinitely Divisible Distributions (John Wiley & Sons, 1986). There we find …
Mateusz Kwaśnicki's user avatar
1 vote
Accepted

If $\mu$ is an infinitely divisible probability measure on $[0,\infty)$, then the Lévy measu...

There are at least three ways to show that $n \mu^{*1/n}$ converges to $\nu$ vaguely in $\mathbb{R} \setminus \{0\}$. Let $X_t$ be the Lévy process such that $X_1$ has distribution $\mu$, and let $f$ …
Mateusz Kwaśnicki's user avatar
1 vote

Quantiles of a Levy process

First of all, $X$ being non-lattice is not enough for $X_t$ being absolutely continuous. A simple counter-example is $$X_t = \sum_{n=1}^\infty \frac{N_t^{(n)}}{n!} \, ,$$ where $N_t^{(n)}$ are indepen …
Mateusz Kwaśnicki's user avatar
1 vote

Probability of exiting on the boundary for a monotone Lévy-type process

(i,ii) Not quite. A trivial counterexample is $\ell(x, y) \equiv 0$. A simple non-trivial counterexample would be something like $$\ell(x,y) = \begin{cases} 1 / (x^{1/2} y^{3/2}) & \text{if $0 < x \le …
Mateusz Kwaśnicki's user avatar
5 votes

Besov regularity of càdlàg functions?

(This is not a complete answer, someone more experience in Besov spaces is welcome to improve it). I do not think there is much relation between these two concepts. Obviously, $D(\mathbb{R})$ only c …
Mateusz Kwaśnicki's user avatar
1 vote
Accepted

Identity for stable Lévy subordinator

It is of course possible to show that the left-hand side is continuous (e.g. using bounds for the derivative of $p_\beta(s, x)$), but there is a more direct way. Observe that $$p_\beta(s, x) = s^{-1/\ …
Mateusz Kwaśnicki's user avatar
1 vote

escape points of Levy processes

This does not seem to be true: take $X_t$ to be a symmetric stable process in $\mathbf{R}$ with index $\alpha > 1$, and $D = (-1, 1) \setminus \{0\}$. Then $X_t$ hits $0$ with positive probability. T …
Mateusz Kwaśnicki's user avatar