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Show that $\sum_{i=0}^{\frac{p-1}{2}} {{\frac{p-1}{2}}\choose {i}}^2 x^{\frac{p-1}{2}-i}$ is...

I am trying to prove that $p$ does not divide the discriminant of the polynomial. It seems like all the prime factors of the discriminant are less than $p$. …
Huy Dang's user avatar
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