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Non-commutative rings and algebras, non-associative algebras, universal algebra and lattice theory, linear algebra, semigroups. For questions specific to commutative algebra (that is, rings that are assumed both associative and commutative), rather use the tag ac.commutative-algebra.

7 votes
2 answers
557 views

Rational powers of ideals in Noetherian rings

Let $R$ be a Noetherian ring, and let $I$ be an ideal of $R$. Fix a rational number $a=\frac{p}{q}$ with $p, q\in \mathbb{Z_\geq 0}$ $q\neq 0$. We define $I_a = \{x \in R: x^q\in \overline{I^p}\}$, wh …
Timothy Wagner's user avatar
6 votes
1 answer
790 views

Radicals of binomial ideals

Let $R=k[x_1,x_2,...,x_n]$ be the polynomial ring in $n$ indeterminates over a field $k$. An ideal (that can be) generated by monomials is called a monomial ideal. For the monomial ideal $M=(m_1,m_2,. …
Timothy Wagner's user avatar
5 votes
0 answers
509 views

Monomial-type ideals in polynomial rings

Let $R=k[x_1,x_2,...,x_n]$ be the polynomial ring in $n$ indeterminates over a field $k$. A monomial in $R$ is an element which is product (with repetitions allowed) of the indeterminates. Monomial id …
Timothy Wagner's user avatar
1 vote

Structure theorem of f.g. modules over a (non) PID

I am unable to write this is in comments. While this is not an answer to your question, a similar structure theorem holds for Principal ideal rings where every finitely generated module is isomorphic …
Timothy Wagner's user avatar
9 votes
3 answers
2k views

(Krull) dimension of any associated graded ring of a ring R equals the dimension of R

I am not sure if this is appropriate for MO. If not, I shall be happy to take it to SE. For a local ring $(R,m)$, given any proper ideal $I$, the (Krull) dimension (from here on dimension means Krull …
Timothy Wagner's user avatar