Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with cv.complex-variables
Search options not deleted
user 102946
Complex analysis, holomorphic functions, automorphic group actions and forms, pseudoconvexity, complex geometry, analytic spaces, analytic sheaves.
3
votes
Accepted
holomorphy in infinite dimensions (holomorphic families of operators)
In addition to the information given by user bathalf15320, I think that a bit more information on the Banach space case could be useful:
Here is a very general theorem about vector valued functions:
T …
- 12.5k
6
votes
Accepted
Does uniform boundedness carry over from the non-negative real axis to closed sectors of $\m...
There is a one-dimensional counterexample: Consider the analytic semigroup $z \mapsto e^{iz}$. This semigroup is bounded on the non-negative real line, but it is not bounded on any sector $\Delta_\del …
- 12.5k
2
votes
Vector valued disc "algebra"
Edit 2018-08-08: Partial positive result added (Theorem 2).
First, here is a counterexample for the case of weak${}^*$-continuity:
Counterexample 1. Let $E = \ell^\infty := \ell^\infty(\mathbb{N}_0) …
- 12.5k
33
votes
Accepted
Why should I look at the resolvent formalism and think it is a useful tool for spectral theory?
Preliminary remark. As mentioned in the comments, I find the notion "resolvent formalism", as well as the description in the Wikipedia article, rather misleading - resolvents are not somekind of forma …
- 12.5k