Numerical evidence suggests that all complex zeros residing in the critical strip $0 < \Re(s) < 1$ of:

$$\frac{\Gamma(s)}{z}Li_s(z) \, \pm \, \frac{\Gamma(1-s)}{z}Li_{1-s}(z)$$

are on the critical line $\Re(s)=\frac12$ for all $z \lt 1$ (with both individual terms $\ne 0$, except when $z=-1$).

I derived two integral expressions for this function that both only converge in the strip for $z \lt 1$,

$$\displaystyle \int_0^\infty  \frac{t^ {s-1} \, \pm \, t^{-s}}{\mathrm{e}^{t}-z}\mathrm{d}t$$

and

$$\displaystyle \int_0^1  \frac{\ln^{s-1}\left(\frac{1}{t}\right) \, \pm \, \ln^{-s}\left(\frac{1}{t}\right)} {1-z\,t}\mathrm{d}t$$

however neither does reveal any further information about their zeros. 

Notes:

 - when $z \rightarrow 0$, the function reduces to $\Gamma(s) \pm \Gamma(1-s)$, for which it has been proven [here][1] that all complex zeros in the strip are on the critical line (and only a finite number lie outside the strip). **Additional observation:** I found that by gradually increasing $z$ from $0$ to $1$ and for each step calculating the 'adjacent' zeros (that I still find to all reside on the line $\Re(s)=\frac12$), their imaginary parts $s$ seem to follow a path connecting a zero of $\Gamma(s) - \Gamma(1-s)$ when $z \rightarrow 0$, uniquely to a zero of the function at $\Gamma(s)\zeta(s) - \Gamma(1-s)\zeta(1-s)$ when $z \rightarrow 1$. The following graph shows these paths with $z$ on the horizontal axis increased by steps of $0.02$ and the imaginary part $s$ at values in $\frac12 + s \,i$ where the function vanishes. The paths that lead to the non-trivial zeros are marked in red. Also tried a similar plot for $z$ decreasing from $0$ to $-1$ and although the paths seem to nicely continue for all non-trivial zeros, I did find that some of the other zeros on the line $z=0$ do not map to zeros on the line $z=-1$ that equals $\Gamma(s)\eta(s) - \Gamma(1-s)\eta(1-s)$.

![enter image description here][2]
      

 - unlike for $\Gamma(s)$ and $\zeta(s)$, there doesn't seem to exist a reflection formula relating $Li_s(z)$ and $Li_{1-s}(z)$.

**Questions:**

1) Are there known counter examples of complex zeros lying off the critical line, but still in the strip (I know there do exist a few complex zeros outside the strip and also that there are real zeros)?

2) Is this phenomenon a consequence of the RH or would a prove of it imply the RH (note that $z=-1$ turns the $Li_s(z)$ into the Dirichlet $\eta(s)$-function that can be directly related to $\zeta(s)$)?

Thanks.


  [1]: http://mathoverflow.net/questions/89324/are-all-zeros-of-gammas-pm-gamma1-s-on-a-line-with-real-part-frac12
  [2]: https://i.sstatic.net/of3W4.png