The Domb numbers are given by
$$D_n=\sum_{k=0}^n\binom{n}{k}^2\binom{2k}k\binom{2(n-k)}{n-k}\ \ \ (n=0,1,2,\ldots).$$
Such numbers have combinatorial interpretation, see, e.g., http://oeis.org/A002895.

I have the following three conjectures on congruences involving the Domb numbers.

**Conjecture 1** (2019). For any odd prime $p$, we have
$$\sum_{k=1}^{p-1}\frac{D_k}k\equiv\left(\frac p3\right)\frac 25pB_{p-2}\left(\frac13\right)\pmod{p^2},$$
where $(-)$ is the Legendre symbol and $B_{p-2}(x)$ is the Bernoulli polynomial of degree $p-2$.

**Conjecture 2** (2020). For any prime $p>5$, we have
$$\sum_{k=1}^{p-1}\frac1k\left(D_k-\frac{4D_{k-1}}{64^{k-1}}\right)\equiv-\frac{16}3p^2B_{p-3}\pmod{p^3},$$
where $B_0,B_1,\ldots$ are the Bernoulli numbers.

**Conjecture 3** (2013). For any prime $p>3$, we have
$$\det[D_{i+j}]_{0\le i,j\le p-1}\equiv\begin{cases}(\frac{-1}p)(4x^2-2p)\pmod{p^2}&\mbox{if}\ p=x^2+3y^2\ (x,y\in\mathbb Z),\\0\pmod{p^2}&\mbox{if}\ p\equiv 2\pmod 3.\end{cases}$$

Conjectures 1 and 3 appeared in Conjecture 79 of my published paper [Open Conjectures on Congruences][1]. I have not made Conjecture 2 public before, I can prove the congruence in Conjecture 2 modulo $p$.

**QUESTION.**  Any ideas towards solving these conjectures?

[1]: http://maths.nju.edu.cn/~zwsun/191o.pdf