Let $M$ be $S^1 \times [-1,1]$, $f$ a [baker map](https://en.wikipedia.org/wiki/Baker%27s_map) on $M$ and for $p, q \in M$ consider $W^s_p$ the stable manifold in $p$ (i.e. the set of points whose forward orbit tend to the forward orbit of $p$) and $W^u_q$ the unstable manifold in $q$ (i.e. the set of points whose backward orbit tends to backwards orbit of $q$).
Let us assume, we have transversality.
Question:

>Let $x\in W^u_p$ and $y\in W^u_q$. Show that there exists a point $t$ so that $t\in W^u_x \cap W^u_y$, if $x$ and $y$ be small close to each other. I want to say that if two point be close to each other their unstable manifold will intersect each other at a point.

> Under which assumption we can prove it the intersection point is unique?

When we draw baker map we easily see they intersect a point but i do not know how can i prove it?

Thanks in advance.