In the book by Elias M.Stein and Guido Weiss "Introduction to Fourier Analysis On Euclidean Spaces" one states in page 268 the following theorem:
> **Theorem 1**:The trigonometric series
$$\underset{m\in \mathbb{Z}^{n}, m\neq 0}\sum |m|^{-(n/2)+1/2}e^{2\pi i m.x}$$
diverges almost everywhere. More particularly,
$$\underset{R\rightarrow\infty}\limsup \,\,|\underset{0<|m|<R}\sum |m|^{-(n/2)+1/2}e^{2\pi i m.x}|=\infty$$

We have noted in the previous theorem for $m=(m_{1},...,m_{n})\in\mathbb{Z}^{n}$ and $x=(x_{1},...,x_{n})\in\mathbb{R}^{n}$:\
$$|m|^{2}=m_{1}^{2}+...+m_{n}^{2}$$
$$m.x=m_{1}x_{1}+...+m_{n}x_{n}.$$
 **My request is:** For a real number $\alpha>0$ consider the trigonometric series
 $$\underset{m\in \mathbb{Z}^{n}, m\neq 0}\sum \frac{e^{2\pi i m.x}}{|m|^{\alpha}}.$$
 For what value of $\alpha$ the previous series is convergent?\
\
 The convergence mode we adopt is the following: The previous series is convergent for $\alpha$ if
 $$\underset{R\rightarrow\infty}\lim {\underset{0<|m|\leq R}\sum \frac{e^{2\pi i m.x}}{|m|^{\alpha}} }$$
 exits.\
 The question is already well elucidated for $n=1$. For $n>1$ the previous theorem asserts that there is divergence for $\alpha=\frac{n}{2}-\frac{1}{2}$.\
 For other kind of convergence mode these question is treated by Stephen Wainger in "Special Trigonometric Series In k-Dimensions."