Let $\mathcal{F}$ be the space of Fredholm operators on a separable Hilbert space $H$ with the topology induced by the operator norm. 
If $X$ is compact,
Atiyah-Jänich proved that
$$[X,\mathcal{F}]\simeq K^0(X). $$
Here $[\cdot,\cdot]$ denotes the set of homotopy classes.

For the equivariant version, for a compact Lie group $G$, let $\mathcal{F}(G)$ be the space of Fredholm operators on $L^2(G,H)$. The group $G$ acts on $\mathcal{F}(G)$ in a natural way. For compact $G$-space $X$, one has 
$$[X,\mathcal{F}(G)]_G\simeq K_G^0(X). $$
Here $[\cdot,\cdot]_G$ denotes the set of $G$-homotopy classes of $G$-maps.
http://www.ams.org/mathscinet/search/publdoc.html?pg1=INDI&s1=121545&vfpref=html&r=42&mx-pid=290354

On the other hand, let $\hat{\mathcal{F}}_*$ be the space of self-adjoint Fredholm operators on $H$ such that its elements have infinite positive as well as infinite negative spectrum. Atiyah proved that
$$[X,\hat{\mathcal{F}}_*]\simeq K^1(X). $$

My question:
is there a equvariant isomorphism for $K_G^1$ as in $K_G^0$?
That is,
$$[X,\hat{\mathcal{F}}(G)_*]_G\simeq K_G^1(X)? $$
As the proof of Atiyah, I think it turns to prove $\hat{\mathcal{F}}(G)_*\rightarrow \Omega \mathcal{F}(G)$ is a $G$-homotopy equivalence.