Let assume $ X= \Omega \times (0,T)  $ where $\Omega \subset \mathbb{R} $ is a bounded open set and $T>0$.

Now define the operator $ \mathcal{A} : C^{‎\sigma‎, \sigma‎/2‎}(‎X‎) \to C^{‎\sigma‎, \sigma‎/2‎‎}(‎X‎) $ in the following way:


>$$
‎‎‎\mathcal{A}‎‎(\phi)(t, ‎x)= \\ \nonumber‎  A_0(x) ‎‎\mathcal{B}(\phi)(t, ‎x, ‎0)+ \int_0^t ‎a(s, ‎x)‎b(s, ‎x) ‎| ‎\phi(s, ‎x)| ‎‎\mathcal{B}(\phi)(t,x,s) ‎ds
$$

such that

>$$ ‎\mathcal{B}(\phi)(t,x,s)=\chi‎_{[s, T]}(t) \, \exp\Big(-\int_s^t ‎\frac{a(\zeta,x) b(\zeta, x)}{c(\zeta, x)}\vert ‎\phi(\zeta, ‎x)\vert ‎\: ‎d‎\zeta‎\Big) ‎ \\ \nonumber‎ 
\times \exp \Big(-\int_s^t [d(\zeta, x)+‎e‎(‎\zeta‎, x)+f(\zeta, x) \chi‎_{‎\omega‎}]\: d‎\zeta ‎\Big)‎.$$

where 

$$ a(t,x) , b(t,x) , c(t,x), d(t,x), e(t,x), f(t,x) \in C^{‎\sigma‎, \sigma‎/2‎} (‎\overline{\Omega} ‎\times ‎(0, ‎T)‎),$$

$\omega \subset \Omega$ and $A_0 \in C^{‎\sigma‎}(‎\overline{\Omega}‎).$ 


In solving a problem related to my thesis, for proving existence of a local solution by classical Contraction Mapping Theorem, I need to prove that the above operator is lipschitz with the standard norm of $C^{‎\sigma‎, \sigma‎/2‎‎}$, but I can't succeed. 

Can someone help me to know whether this opeator can be lipschitz or not, in order to use other way to find a local solution instead of classical Contraction Mapping Theorem.

Thank you.