A power tower of a number $x$ is typified by 

$$ x^{x^{x^{x^{x^{x^{x^{x^{x^x}}}}}}}}.$$ 

Here, however, we take the liberty of referring to the set $T$ of "$\{2,3\}$-power towers"; i.e., numbers

$$x_1^{x_2^{x_3^{ \cdots\cdots^{x_k}}}},$$

where each $x_h$ is $2$ or $3,$ and $k \geq 2.$  Let $T_2$ be the subset of $T$ consisting of towers rising from $x_1=2.$  Let $R$ be the sequence of ranks of towers in $T_2$ when all the towers in $T$ are jointly ranked.  

The first $15$ terms of $R$ are $$1, 2, 4, 7, 8, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29.$$  What are the next terms?       

Note that $T$ can be obtained recursively from $t_2 = \{2^2,2^3,3^2,3^3\}$ by defining

$$t_n =2^{t_{n-1}} \cup 3^{t_{n-1}}$$

for $n \geq 3;$  then $T$ is the union of the sets $t_n$ for $n \geq 2.$
 
For a top-first version of the problem, change $x_1=2$ to $x_k=2,$ where $k$ is the height of the tower.  Then the first $17$ terms are $$1,3,4,6,10,11,12,15,16,19,20,23,24,25,26,27,28,\ldots.$$  Here, too, the question is: what are the next terms?

Added later:  Thanks, Yaakov, you are right, so my question is, what are the positions of the numbers in $T_2$ in the sequence in the sequence $(1,2,3,\ldots)$.  I have the first $30$ positions (or ranks) and would like to see a method for finding more terms.

It may help to see a list of the first $20$ towers ranked:

$$8 = 2^2$$
$$9 = 2^3$$
$$16 = 2^{2^{2}}$$
$$27 = 3^3$$
$$81 = 3^{2^{2}}$$
$$256 = 2^{2^{3}}$$
$$512 = 2^{3^{3}}$$
$$6561 = 3^{2^{3}}$$
$$19683 = 3^{3^{2}}$$ 
Continuing with tuple notation instead of tower notation:
$(2,2,2,2), (3,2,2,2), (2,3,3), (3,3,3), (2,3,2,2), (3,2,2,2), (2,2,2,3), (3,2,2,3), (2,2,3,2), (3,2,3,2), (2,3,2,3).$

My method, so far, has been by computer sort, which reaches overflow pretty quickly.  Surely there must be a more satisfactory method.  A related question:  what is the position (or rank) of $(2,2,2,2,2,2)?$