By the circulant matrix $C$ in $M_n(\mathbb{R})$, we mean that 
 $$C=[e_n|e_1|\cdots|e_{n-1}]$$ where $e_1,\cdots,e_n$ are the standard basis vectors in $\mathbb{R}^n$.  It is well-known that  
$$C=\mathbf{F}\operatorname{Diag}(1,w,\cdots,w^{n-1})\mathbf{F}^{-1}$$
where $\mathbf{F}$ is just the discrete Fourier matrix and $w=\exp(\frac{2\pi i}{n})$


 Let $U=(u_{ij})$ be a strictly upper triangular matrix with $u_{ij}\in \{0,1\}$ . Is $C+U$  diagonalizable?