I'm given two matrices in $SL_2(\mathbb{Z})$

$$
A = \left(\begin{array}{cc}
       2 & 3\\
       3 & 5
     \end{array}\right), \ \
B = \left(\begin{array}{cc}
       5 & 3\\
       3 & 2
     \end{array}\right).
$$

Then the group $\langle A, B \rangle$ is free of rank 2. Now my problem is to prove that $\langle A, B \rangle$ does not contain any matrix of the form

$$
  \left(\begin{array}{cc}
       1 & n\\
       0 & 1
  \end{array}\right)
$$

with $n\in\mathbb Z$ nonzero. That is, no such matrix can be obtained from products of $A$ and $B$ and their inverses.

I started by writing
$$
  \left(\begin{array}{cc}
       0 & 1\\
       - 1 & 0
     \end{array}\right) \longrightarrow x, \left(\begin{array}{cc}
       0 & 1\\
       - 1 & 1
     \end{array}\right) \longrightarrow y,
A \longrightarrow (y x y^{- 1} x^{-1})^2,
B \longrightarrow (y^2 x y^2 x^{- 1})^2,
$$
but then did not get any further. 

Any help is highly appreciated.