Let $X$ be a Banach space and
$$\mathrm C_0(\mathbb R,X):=\{f\colon\mathbb R\to X\colon f \text{ is continuous and } \lim\limits_{|t|\to\infty}f(t)=0\}$$
normed by
$$\|f\|:=\sup\limits_{t\in\mathbb R}\|f(t)\|, \quad f\in \mathrm C_0(\mathbb R,X).$$
Let $(U(t,s))_{t\ge s}$ denote an evolution family of bounded linear operators on $X$ satisfying:
$$U(t,r)U(r,s)=U(t,s)$$
and $U(t,t)=\operatorname{Id}$, the identity on $X$, for all real numbers $s\le r\le t$. Let $(R(t))_{t\ge 0}$ denote the right shift semigroup:
$$(R(t)f)(s)=f(t-s)$$
for all $s\in\mathbb R$, $t\ge 0$, and $f\in \mathrm C_0(\mathbb R,X)$.

Does the evolution family and the right shift semigroup commute? More precisely, it is true that for any $T\ge 0$
$$U(t,t-s)R(s)f=R(s)U(t,t-s)f$$
holds for all $t,s\in[0,T]$ and $f$ from some appropriate space (which?)?