Here are some examples illustrating the genuine necessity of noetherian assumptions:  

 **1) Every scheme with just one point is the spectrum of a local artinian ring?**   
This is true   for every noetherian one point scheme and false for every non-noetherian one point scheme.  
A non-noetherian (and thus non-Artinian) example :  $\operatorname {Spec}(\mathbb Q[T_1,T_2,T_3,\cdots]/\langle T_1^2,T_2^2,T_3^2 \rangle )$    

**2) Every scheme has a closed point?**  
This is true for every noetherian scheme (actually for any quasi-compact scheme), but there exist schemes without any closed point: [Qing Liu](https://www.math.u-bordeaux.fr/~qliu/Book/), Chapter 3, Exercise 3.27, page 114.     

**3) Injective modules give injective sheaves?**  
If $I$ is an injective module over the  ring $A$, then the associated quasi-coherent sheaf $\tilde I$ on  $X=\operatorname {Spec}(A)$ is an injective sheaf of $\mathcal O_X$- Modules if $A$ is noetherian but is not necessarily injective for $A$ non-noetherian: [SGA6](http://library.msri.org/books/sga/sga/pdf/sga6.pdf), Exposé II, Appendice I Un contre-exemple de Verdier, page 195.   

**4) A finitely presented sheaf  is coherent?**   
Given  on a scheme $X$ a sheaf of $\mathcal F$ of $\mathcal O_X$-Modules, does the existence of an open covering $(U_i)$ of $X$ for which one has exact sequences $\mathcal O_{U_i}^{n_i}\to \mathcal O_{U_i}^{m_i}\to \mathcal F\vert _{U_i}\to 0$ imply that $\mathcal F$ is coherent?    
The answer is yes if $X$ is noetherian (or even locally noetherian) but no in general: there exist non-noetherian rings $A$ such that the structural sheaf $\mathcal O_X$ on $X=\operatorname {Spec}(A)$ is not coherent!