I'm interested in estimating the following quantity 

\begin{equation}\lim_{k \to \infty} \sum \limits_{i=1}^l \sum \limits_{l_1 = 0}^{i} {{nk-k}\choose{l_1}} \Big( \frac{1}{k}\Big)^{l_1} \Big( \frac{k-1}{k}\Big)^{nk - k -l_1} {{k}\choose{i-l_1}} \Big( \frac{l}{nk+1}\Big)^{i-l_1} \Big( \frac{nk+1-l}{nk+1}\Big)^{k-i + l_1}
\end{equation} 

where $l$ satisfies $1 \leq l \leq nk$ and $l_1, l_2$ satisfy $l=l_1+l_2$. The above sum arises in a problem concerning the sum of independent random variables, where $nk-k$ variables have image $\{0,k\}$ and $k$ variables have image $\{0, \frac{nk+1}{l} \}$ . Given that $l$ of these variables are non zero, we assume that there are $l_1$ non zero variables of the first kind and $l_2$ variables of the second kind, hence $l_1+l_2=l$. The probability of a variable with the first image of being non zero is $p_1=\frac{1}{k}$ and of the seond image $p_2=\frac{l}{nk+1}$. So the above quantity is the probability that at most $l$ variables are non zero. 

> **Question**: Is the above quantity greater or equal to $1/e$ ?

Any help or suggestions of techniques that might crack the problem would be much appreciated.