I think it have. Probably infinitely many.

\begin{aligned}
x =& 6882627592338442563 \\
y =& 4866752642924153522 \\
a =& 4096 \\
b =& -8192 \\
c =& 1 \\
d =& -2 \\
t =& 4 \\
\end{aligned}

Found this way.

Fix $c=1,d=-2$ and solve the Pell equation with large $x,y$.

Then $a=2^{2^t-t}$ and $b= -2 \cdot 2^{2^t-t}$ solves the first equation.

**Added**

So $x^2 - 2 y^2=1$ have arbitrary large solutions. Fix $t$.

Then $ 2^{2^t-t} (x^2 - 2 y^2) = 2^{2^t-t}$.