Consider the following function in $\mathbb{R}^3$:
$$
f_t(x)=(1+|x|^2)^{-\alpha}e^{-g(x)t},\,\,\,\,\, \text{where}\,\, g(x)=\frac{x^2_1\cdot x^2_2}{1+|x|^2},
$$
where $\frac{1}{2}<\alpha<1$, and the parameter $t$ satisfies $0<t<1$.

I'm interested in the behavior near the origin of the Fourier transform of $f_t(x)$ (in the distributional sense). To be more precisely, let  $g_t(\xi)=\mathcal{F}{f_t(x)}$ denote the Fourier transform of $f_t(x)$. Since in the limiting case $t=0$, the Fourier transform can be explicitly computed and we have (using properties of Bessel functions)
$$
|g_0(\xi)|\leq C |\xi|^{-3+2\alpha}, \,\,\,\, |\xi|\leq 1.
$$

My question is that does this property keep valid uniformly for $0<t<1$? i.e., do we have a constant which doesn't depend on t such that 
 $$
|g_t(\xi)|\leq C |\xi|^{-3+2\alpha}, \,\,\,\, |\xi|\leq 1,\,\,\,0<t<1 ?
$$
It seems that one difficulty is that the Fourier transform of $e^{-g(x)t}$ is not quite easy to handle. I tried to take the Taylor expansion of this, but it seems to get more troubles. Comments and references are welcome.