The answer is no. For every nonstandard model of arithmetic $M$ there is another model $M'$ having exactly the same domain, the same clusters, with the same cluster order and cluster addition, but different addition functions $+^M\neq +^{M'}$. 

Given any $M$, construct a model $M'$ by shifting the individuals within some nonstandard cluster, but fixing all other individuals. That is, $M$ will be isomorphic to $M'$ by that shifting process. So the models $M$ and $M'$ will have the same domain and the same clusters, and their clusters will be in the same order, and since cluster addition is well defined with respect to finite shifts, the models have the same cluster addition operation. But they have different addition operations. 

Conclusion: the addition operation of the model is not determined by the order relation and addition operation on the clusters.