`Does anyone have any advice or help on how to tackle the following problem` ?: 
$$
\mbox{Show that the function}\
\operatorname{f}\left(r\right) =
\int_{0}^{\infty}\operatorname{J}_{0}\left(rx\right)
{\rm e}^{-ax^{2}}\cos\left(x\right)x\,{\rm d}x\,,\ r \geq 0
$$
`is positive` beyond a certain value for $a$ positive. Would it be possible to show that the exact threshold for a is the one needed to ensure that it is positive at the origin?

Some notes:
 - It is easy to calculate the exact value of a beyond which $\operatorname{f}\left(0\right)$ is positive. Also,
$\operatorname{f}\left(r\right) \to 0$ as $r \to \infty$.
 - So if I can prove that f cannot have any zeros (or local minima) it would prevent it from becoming negative.
 - I am not sure though if looking at the critical points of $\operatorname{f}$ is the right way to go.

Thanks in advance for any help :) Even help in gauging how easy/difficult this question is is welcome.