OOPS: As Sándor points out, I missed the assumption that the ring is local, in the following:

Inside 3-space, glue together a plane $y=0$ transversely with a parabola
$z=0, x=y^2$ and a line $z=1, x=0$ meeting it in a separate point.
This is reduced, and I'm pretty sure its depth is $1$. Because of the
plane, its dimension is $2$.

Now cut it with $x=0$, which cuts the plane to a line and the parabola to a double point leaving the line alone. Hence $x$ is a zero divisor in
$k[x,y,z]/(\langle y\rangle \cap \langle z,x-y^2\rangle \cap \langle z-1,x\rangle)$, and cutting with it drops the dimension from $2$ to $1$.

The resulting space is generically reduced, but not reduced, so I'm 
pretty sure its depth is $0$.