Skip to main content
1 of 4
timur
  • 3.3k
  • 1
  • 36
  • 42

Already the fact that $u$ is a tempered distribution and is weakly harmonic implies that $u$ is a polynomial. Then observe that the only polynomial in $L^p({\mathbb R}^n)$ is zero. Also, you do not need to talk about "almost everywhere" because weakly harmonic functions are smooth (in fact analytic).

timur
  • 3.3k
  • 1
  • 36
  • 42