Skip to main content
2 of 2
Added link
David Roberts
  • 35.5k
  • 11
  • 124
  • 349

Fubini's theorem without completeness or $\sigma$-finiteness conditions

The usual Fubini's theorem(see the Wikipedia article for example) assumes completeness or $\sigma$-finiteness on measures. However, I think I came up with a proof of the Fubini's theorem without those assumptions. Am I mistaken?

I restate the theorem to avoid confusion: If a function is integrable on a product measure space, its integral can be calculated by iterated integrals.

The idea of my proof is to use a fact that if a function is integrable on a product measure space, the function must be zero outside a $\sigma$-finite subset of the product measure space.

Makoto Kato
  • 1.2k
  • 8
  • 19