I think the order structure you describe is identical to the [face lattice](https://en.wikipedia.org/wiki/Convex_polytope#The_face_lattice) of the $d$-cube. You then ask about an order preserving and surjective map between two such lattices, but not in a standard way, that is, e.g. not like an [order embedding](https://en.wikipedia.org/wiki/Order_embedding). It looks more like you try to find the face lattice of $Q_d$ as a "sub-lattice" in $Q_{d+k}$, but in kind of  a [graph minor](https://en.wikipedia.org/wiki/Graph_minor) sense.

The set $S(Q_d)$ can also be identified with $\{*,0,1\}^d$, i.e., the set of sequences of length $d$ with these three symbols. One way to map $S(Q_{d+k})\to S(Q_d)$ surjectively and order-preservingly is by restriction, that is, e.g. by deleting the $k$ first entries of the sequence. This corresponds to the geometric operation of *projection*, as we project the $(d+k)$-cube onto one of its $d$-dimensional faces (which is a $d$-cube).

There are other such maps, though. Look at the following picture, which is meant to partially visualize a map $S(Q_3)\to S(Q_2)$.

<img src="https://i.sstatic.net/o1W7Z.png" width="330" />

This map can be completed to a projection onto some face of $Q_3$ (the face is not uniquely determined). But there are other ways to complete this map, which does not correspond to such a projection:

 - The red vertices of $Q_3$ are mapped to the red vertices of $Q_2$.
 - The blue edges of $Q_3$ are mapped to the blue edges of $Q_2$.
 - The green faces of $Q_3$, their edges, and their non-red vertices are mapped to the green edges of $Q_2$.
 - All other subcubes of $Q_3$ ($Q_3$ itself, the non-green faces and the the non-blue edges) are mapped to $Q_2$ itself.

This is not a projection, since in a projection from $Q_3$ to $Q_2$ only two faced would be mapped to all of $Q_2$.