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edited Mar 9, 2012 at 17:21

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Topological type $x_0^2+x_1^2+x_2^2+ x_3^2+x_4^2 = 0$ in $\mathbb P^4$

Let's consider projective variety $V$ given by th equation $x_0^2+x_1^2+x_2^2+ x_3^2+x_4^2 = 0 \ $ in $\mathbb CP^4$.

I was wondering what is the Picard group of $V$ ? Or cohomology ring of $V$ ?

ag.algebraic-geometry at.algebraic-topology

asked Mar 9, 2012 at 17:16

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