If $P$ is a degree $ l $ differential operator then
$ |Pu||_s < C || u ||_{s+l}$ , $\forall u, s. $
Now take $s=-k$, $P=\nabla^l$. (Sorry. There seems to ne a problem with MathJaxs
If $P$ is a degree $ l $ differential operator then
$ |Pu||_s < C || u ||_{s+l}$ , $\forall u, s. $
Now take $s=-k$, $P=\nabla^l$. (Sorry. There seems to ne a problem with MathJaxs