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Aaron Meyerowitz
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I'd guess that perhaps they can be supported on $G$ but that it is not always the case that they must be. Suppose that the entropy for both $X$ and $Y$ should be $1$. Then indeed if $n=2m$ we should (I'd think) take $X=Y=\lbrace0,m\rbrace$ with equal weighting and then get $X+Y=Z.$ But for $n$ odd (and composite) I'd think that $X$ and $Y$ should each be $\lbrace0,g\rbrace$ for some $g \ne 0$ with $X+Z$ supported on the set $\lbrace 0,g,2g \rbrace.$ with probabilities $1/4,1/4$ and $1/2.$ Of course we can also shift and have $X=\lbrace0,g\rbrace$ and $Y=\lbrace0,-g\rbrace.$ In any case, there is no gain (nor loss) in confining $g$ to a proper subgroup.

Aaron Meyerowitz
  • 30.1k
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  • 104