I am wondering if there are any references that would help me with the following problem:

Let $p>2$ be a prime number, $n \in \mathbb{Z}^+$ odd such that $(n,p)=1$, $\chi$ an imaginary quadratic character of conductor $n$, and $\omega$ the Teichmuller character.

I'm trying to calculate the sum
\begin{equation}
\sum_{a=1}^{(np-1)/2} \chi\omega^{-1}(a)(-1)^a.
\end{equation}

This sum almost reminds me of a quadratic Gauss sum (I know this is a big stretch) which I've seen can be computed using Fourier analysis.  From my basic understanding (see [Rodgers - Fourier series, Gauss sums, and quadratic reciprocity](https://mast.queensu.ca/~br66/421/gauss_sums_handout.pdf)), the computation relies on the fact that 
\begin{equation}
\sum_{a=0}^{p-1}\left(\frac{a}{p}\right)e^{2\pi  i a/p} = \sum_{a=0}^{p-1} e^{2\pi i a^2/p}
\end{equation}
(here $(a/p)$ is the Legendre symbol) and defining $f(x) = \sum_{a=0}^{p-1} e^{2\pi i (a+x)^2/p}$, which is periodic on $\mathbb{R}$, we compute $\hat{f}(x)$ and find that
\begin{equation}
\sum_{a=0}^{p-1}\left(\frac{a}{p}\right)e^{2\pi  i a/p}= \sum_{a = -\infty}^{\infty}\hat{f}(a) = \text{a computable integral}.
\end{equation}

In my naive attempt to mimic this process, I think I fail (or just can't see) how to write $\sum_{a=1}^{(np-1)/2} \chi\omega^{-1}(a)(-1)^a$ as a sum involving only exponentials and then coming up with a periodic function $f(x)$ that is my character sum when evaluated at 0.  Because it is quite a stretch to compare my sum to a Gauss sum, I'm now thinking it is a bad idea to try to mimic this computation.

**Questions:**  
- Is there a more general method out there for computing character sums like the one I have using Fourier analysis?  

- Are there any other methods/theory that might help me out in calculating this sum? 

I would also be happy if I could somehow factor this sum in $\mathbb{Q}(e^{2\pi i/(p-1)})$.  I'm reminded of Stickelberger's theorem, where part of the proof involves finding the prime factorization of a certain Gauss sum (here I go again with the comparison).  I know that the sum I'm looking at will not behave as nicely as the Gauss sum in the proof of Stickelberger's, but I am wondering,

- Is there is a general theory for finding the $\mathcal{P}$-adic valuation of a character sum, where $\mathcal{P}$ lies above $p$ in whatever field the character sum lives in.