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Matthias Ludewig
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Yes, that doesn't make much of a differerence. For the finite-dimensional case the theorem is proved by induction (just in each step, take one element of a complementary subspace and expand the functional on it), and for the infinite dimensional as well, with the additional help of Zorn's lemma.

Matthias Ludewig
  • 9.9k
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  • 71