I confirm the Anton's answer (No, and the phenomenon is essentially local), but I suggest another explanation which works for C^1  2-dimensional metrics. 

We will look for a counterexample  in the class of   metrics such that they  are C^2 everywhere except for some line, where they are  C^1.  Then, it is possible and relatively easy to cook an example such that the curvature of the metric is discontinuous at this special line; you can do it in the class of conformally flat metrics such that the conformal coefficient depends on one variable only and the line is where this variable is a constant. 

Since in order to determine the curvature of a metric you only need  the distance function corresponding to this metric, and distance function does not depend on how smooth is your atlas,  you can not make this metric smooth by the change of the atlas.