Theorems V in [this paper][1] of [L.E. Dickson][2] states that the following two sets are equal. $$E=\{a^2+b^2+2c^2 \ | \ a,b,c \in \mathbb{Z}\} \ \text{ and } \ F=\mathbb{N} \setminus \{4^k(16n+14) \ | \ k,n \in \mathbb{N}\}.$$ Let $\mathbb{A}$ denote $\mathbb{N}$ or $\mathbb{Z}$. Consider the following set (where $u \cdot v$ denotes the usual [dot product][3]): $$E(\mathbb{A}) = \{\|u \|^2 + |u \cdot v| \text{ such that } u,v \in \mathbb{A}^3 \text{ and } \|u \| = \|v \|\}.$$ Let $u= (a,b,c)$, $v = (b,-a,c) \in \mathbb{Z}^3$. Then $\|u \| = \|v \|$ and $\|u \|^2 + |u \cdot v| = a^2+b^2+2c^2.$ It follows that $E \subseteq E(\mathbb{Z})$. But surprisingly, the computation below suggests that $E(\mathbb{Z})=F$ also, which would be an extension of Dickson's theorem. **Question 1**: Is it true that $E(\mathbb{Z})=F$? The computation suggests also the following question: **Question 2**: Is it true that $E(\mathbb{N}) = F \setminus \{ 5, 23, 29, 65, 167 \} $? *Application*: [this answer][4] proves that the form $\| A\|^2$ covers every natural number for $A \in M_3(\mathbb{Z})$. A positive answer to Question 2 would prove this result for $A \in M_3(\mathbb{N})$. ___ **Computation** sage: L=[] ....: for a1 in range(-12,12): ....: for a2 in range(-12,12): ....: for a3 in range(-12,12): ....: for b1 in range(-12,12): ....: for b2 in range(-12,12): ....: for b3 in range(-12,12): ....: if a1**2+a2**2+a3**2==b1**2+b2**2+b3**2: ....: n=a1**2+a2**2+a3**2+a1*b1+a2*b2+a3*b3 ....: L.append(n) ....: l=list(set(L)) ....: l.sort() ....: set(range(255))-set(l) ....: {14, 30, 46, 56, 62, 78, 94, 110, 120, 126, 142, 158, 174, 184, 190, 206, 222, 224, 238, 248, 254} The research of the above sequence in OEIS provides exactly one result: [A055039][5] `Numbers of the form 2^(2i+1)*(8*j+7)`. sage: L=[] ....: for a1 in range(25): ....: for a2 in range(25): ....: for a3 in range(25): ....: for b1 in range(25): ....: for b2 in range(25): ....: for b3 in range(25): ....: if a1**2+a2**2+a3**2==b1**2+b2**2+b3**2: ....: n=a1**2+a2**2+a3**2+a1*b1+a2*b2+a3*b3 ....: L.append(n) ....: l=list(set(L)) ....: l.sort() ....: s=set(range(1484))-set(l) ....: S=[] ....: for i in s: ....: f=list(factor(i)) ....: a=f[0][0] ....: b=f[0][1] ....: if a<>2: ....: S.append(i) ....: elif Integer(b).mod(2)==0: ....: S.append(i) ....: elif Integer(i/(2**b)).mod(8)<>7: ....: S.append(i) ....: S.sort() ....: S ....: [5, 23, 29, 65, 167] [1]: https://mathscinet.ams.org/mathscinet-getitem?mr=1561323 [2]: https://en.wikipedia.org/wiki/Leonard_Eugene_Dickson [3]: https://en.wikipedia.org/wiki/Dot_product [4]: https://math.stackexchange.com/a/2967989/84284 [5]: http://oeis.org/A055039