**Summary** I recently defined some numbers which obey multiplication but not addition. To my surprise after some heuristic manipulations (ignoring convergence), it seems I can express the creation and annihilation operators from quantum mechanics in terms of these numbers! I am now interested in these numbers in their own right. **Question** Using the below arguments how does one calculate the $( \sum_{0 < R \leq 1} \hat R)^\dagger | \phi \rangle$ where one can define: $$ I - (I + \underbrace{\sum_{0 < R < 1}\hat R}_{\hat O} )^{-1} = A^\dagger$$ where $I$ is the identity. **Hat Numbers** We define the following numbers $$\hat 1 = |1 \rangle \langle 1 | + |2 \rangle \langle 2 | + |3 \rangle \langle 3 | + \dots $$ $$\hat 2 = |1 \rangle \langle 2 | + |2 \rangle \langle 4 | + |3 \rangle \langle 6 | + \dots $$ $$\vdots$$ In general, $$ \hat n = |1 \rangle \langle n | + |2 \rangle \langle 2n | + |1 \rangle \langle 3n | + \dots $$ We notice the following: $$ \hat x \hat y = \hat y \hat x = \hat (xy)$$ For example: $$ \hat 2 \cdot \hat 2 = \hat 4$$ Now we also their can create fractions by taking hermitian conjugate of the hat numbers: For example, $$ \hat 2^\dagger = |2 \rangle \langle 1 | + |4 \rangle \langle 2 | + |6 \rangle \langle 3 | + \dots$$ Then we can define rational numbers now as (again for example): $$ \hat {\frac{3}{2}} = \hat 3 \hat 2^\dagger $$ **Creation and Annihilation operators** One can define a creation operator: $$ A^\dagger | n \rangle = | n+1 \rangle$$ In fact, $$ A^\dagger = |1 \rangle \langle 2 | + |2 \rangle \langle 3 | + |3 \rangle \langle 4 | + \dots$$ Now, $\hat 1$ is the identity element and if one allows for the geometric series: $$(\hat 1 - A^\dagger)^{-1} = \hat 1 + \hat A^{\dagger} + \hat A^{\dagger 2} + \hat A^{\dagger 3} + \dots $$ One also can express the above series using the number operators: $$ (\hat 1 - A^\dagger)^{-1} = ( \sum_{0 < R \leq 1} \hat R)^\dagger $$ where $( \sum_{0 < R \leq 1} \hat R)$ represents the sum of all **rational** hat numbers less than $1$. I don't have a rigorous proof of the above equation but am very confident it is correct (in the sense the LHS and RHS have the bra-ket notation).