Let $A$ be a local selfinjective algebra with indecomposable module $M$. Let $N=A \oplus M$. When there is an indecomposable module $U$ not in $add(N)$, having finite $add(N)$-resolution for some choice of $A$ and $M$? This is not possible in general due to the following examples: - $A=K[x]/(x^n)$ for arbitary $M$ - $A$ arbitrary and $M$ simple.