A standard example of an ind-scheme over a field $\mathrm{k}$ which is not a $\mathrm{k}$-scheme is $\mathrm{k}((\varepsilon))$. My question is how to prove that rigorously? Or maybe the better way to put that would be - why isn't it a $\mathrm{k}$-sub-scheme of a $\mathrm{k}$-scheme $\prod_{-\infty}^{\infty}\mathbb{A}_{\mathrm{k}}^1$?
Why isn't $\mathrm{k}((\varepsilon))$ a $\mathrm{k}$-scheme?
Michal Zydor
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