Let $\mathfrak g$ be a complex Lie algebra. If $\mathfrak g$ is semisimple then its real forms are completely understood. In particular there is a compact real form of $\mathfrak g$, which is unique up to inner automorphism. 

Suppose $\mathfrak g$ is **not** semisimple and write $\mathfrak g = \mathfrak r \ltimes \mathfrak s$ using the Levi-Malcev theorem, where $\mathfrak r$ is the radical of $\mathfrak g$ and $\mathfrak s$ is a maximal semisimple subalgebra. **Assume that $\mathfrak g$ has a real form**. My question is:

>Can a real form $\mathfrak g_0$ of $\mathfrak g$ be taken so that   $\mathfrak g_0 = \mathfrak r_0 \ltimes \mathfrak s_0$, $\mathfrak r_0$ the radical of $\mathfrak g_0$ and $\mathfrak s_0$ a maximal semisimple subalgebra of $\mathfrak g_0$ which is a compact real form of $\mathfrak s$?