Let $A=A(d)$, and $B=B(d)$ be (sequences of) deterministic positive-definite $d \times d$ matrices and let $X$ be an $n \times d$ random matrix with iid rows from $N(0,A)$. Let $R$ be the resolvent of the (recaled) empirical covariance matrix $S := X^\top X$, given by  $R(z) := (S-z I_d)^{-1}$ for any $z \in \mathbb C^+$, and define $m(z) := \mathbb E[\mbox{tr}(BR(z))]$.

Let $\gamma \in (0,\infty)$ be fixed.

**Question.** Assume that $A$ and $B$ have limiting spectral distributions as $d \to \infty$. In the limit $n,d \to \infty$ such that $d/n \to \phi$, what is the value of $m(z)$ ?

Notes
---
- I'm only interested in computations for small $z$, i.e $z \to 0$.
- If it helps, it may also be assumed that $BA^{-1}$ has a limiting spectral density.


Solution for the case $\phi \lt 1$
----
 WLOG, assume $n \ge d + 2$. Then, it is a standard result that 
$$
\mathbb E R(0) = \mathbb E (X^\top X)^{-1} = \frac{1}{n-d-1}A^{-1}.
$$

We deduce that
$$
m(0) = \frac{1}{n-d-1}\mbox{tr}(B A^{-1}) = \frac{d}{n-d-1}\overline{\mbox{tr}}(B A^{-1}) \to \frac{\phi}{1-\phi}\cdot\lim_{d \to \infty} \overline{\mbox{tr}}(BA^{-1}),
$$

where $\overline{\mbox{tr}} := (1/d)\mbox{tr}$ is the normalized trace operator.