Let $D$ be an integer number and let $\chi$ be the Dirichlet character defined by 
$$\chi(m) = 0 \text{ if $m$ even, } \chi(m) = (D/m) \text{ if $m$ odd,}$$
where $(D/m)$ denotes the Jacobi symbol. Let us denote by $\zeta_D(s)$ its L-series:
$$ \zeta_D(s) = L(s,\chi) = \sum_{n = 1}^\infty \frac{\chi(n)}{n^s} = \prod_p \frac{1}{1-(D/p)p^{-s}},$$
where $(D/p) = 0$ if $p | 2d$.

For $s > 1$ there are the following bounds:
$$\frac{\zeta(2s)}{\zeta(s)} = \prod_p \frac{1}{1+p^{-s}} \leq \zeta_D(s) \leq \prod_p \frac{1}{1-p^{-s}} = \zeta(s).$$
Both of them become trivial for $s = 1$. Still, $\zeta_D(1)$ is a finite positive number for $D < 0$.
> Consider the sequence
$$ \zeta_{-d}(1),\, d = 1,2,3,\ldots$$ 
Is this sequence bounded above or below? If yes, what is an upper or lower bound?