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Number of partitions of a number on a combinatorial bracelet

Suppose we have a combinatorial bracelet composed of natural numbers.

What is the number of different bracelets whose elements sum up to a previously fixed natural number N?

Also, are there any results if we add a constraint that the number of beads on the bracelet is always odd?

P.S. Any good upper bounds are also helpful.

(EDITED in the light of the comments below)