Is the given expression, monotonically increasing or decreasing with increasing x?

$\frac{1}{x \log(x)} \sum_{i=1}^{\infty} \frac{\mu(i)}{i} x^{1/i}$

EDIT: This is the derivative of the prime counting function $\pi(x)$ w.r.t. x, ie.,
$\frac{d\pi(x)}{dx} = \frac{1}{x \log(x)} \sum_{i=1}^{\infty} \frac{\mu(i)}{i} x^{1/i}$