Let $H$ be a Hilbert space and ${\mathcal A}$ a von Neumann algebra in $B(H)$. Let us endow ${\mathcal A}$ with the topology of pointwise convergence with the Hermitian adjoint operator, i.e. a net $A_i\in {\mathcal A}$ tends to 0 in ${\mathcal A}$ if
$$
\forall x\in H\qquad A_ix\overset{H}{\underset{i\to\infty}{\longrightarrow}}0 \quad\&\quad
A_i^*x\overset{H}{\underset{i\to\infty}{\longrightarrow}}0.
$$
The algebra ${\mathcal A}$ with this topology has totally bounded sets $S\subseteq {\mathcal A}$, which I believe, are described by the property
$$
\forall x\in H\qquad \text{the sets $\{Ax;\ A\in S\}$ and $\{A^*x;\ A\in S\}$ are totally bounded in $H$}
$$  
Let $u:{\mathcal A}\to{\mathbb C}$ be a linear functional, which is *continuous on every totally bounded set (equivalently, on each compact set) $S\subseteq {\mathcal A}$* in this sense (with respect to this topology induced from ${\mathcal A}$ to $S$).

Question:

> does this mean that $u$ is a restriction on ${\mathcal A}$ of some functional  $v\in B(H)_*$ (from the predual of $B(H)$)?