In his remarkable book [On the Sphere and Cylinder][1], where he came tantalizingly close to discovering calculus, Archimedes showed that the area of the portion of the sphere contained between a pair of parallel planes cutting the surface depends *only* on the distance between the planes. This fact, which has been dubbed [Archimedes hatbox theorem][2], is now a standard exercise in many calculus texts, and is even commemorated on [the back of the Fields medal][3] (if you look closely, you will see a sphere inside a cylinder in the background). <img src="https://i.sstatic.net/ZKPoU.png" width="160"> Conversely, [Blaschke][5] showed that the only convex surface with this slab area property is the sphere. Indeed it is a simple exercise in classical differential geometry to check that any smooth convex surface with the slab area property must have constant curvature. But can one still characterize the sphere if we fix the distance between the planes: >**Question:** Let $S$ be a convex surface of maximal width $w$. Suppose that for some constant $0<h<w$, the area of the portion of $S$ trapped between every pair of parallel planes separated by the distance $h$ and both intersecting $S$ is constant. Does it follow then that $S$ is a sphere? The *maximal width* $w$ here is the length of the largest possible projection of $S$ into a line. Thus the condition $h<w$ ensures that $S$ is never contained entirely in between the planes, whenever both planes intersect it. Although this is known to be an open problem, and one would assume was at least in the back of Blaschke's mind, I am not aware if it has been explicitly mentioned anywhere. [1]: https://en.wikipedia.org/wiki/On_the_Sphere_and_Cylinder [2]: http://mathworld.wolfram.com/ArchimedesHat-BoxTheorem.html [3]: http://www.mathunion.org/general/prizes/fields/details/ [4]: https://i.sstatic.net/ZKPoU.png [5]: https://link.springer.com/book/10.1007%2F978-3-642-47392-0