$\newcommand{\Fun}{F_\mathrm{un}}$There were lots of "Fun with $\Fun$" ([field with one element][1]) recent years. One of the points is that it provides bridge between geometrical and combinatorial questions, i.e. in the limit case $q=1$ geometry disappears and combinatorial structure distills, on the other hand looking through $F_1$ glass on combinatorics one may try to lift it to geometric picture over $F_q$/any field. My question is about giving examples of that kind. **Question:** What are some combinatorial/probabilistic identities/concepts which have nice $\Fun$ interpretation and might be lifted to nice geometric identities/concepts over $F_q$/any field ? Something similar to the example below: ------------------------ **Example:** (See https://mathoverflow.net/questions/299581/is-there-a-lift-of-the-q-vandermonde-identity-to-some-geometric-motivic-identi?noredirect=1&lq=1) ***Combinatorial side:*** Consider [Vandermonde identity][2]: $$ \binom{m + n}{k} =\sum_{j} \binom{m}{k - j} \binom{n}{j} $$ ***Probability side:*** Consider $n+m$ balls, $m$ white, $n$ black, what is the probability to choose $k-j$ white, $j$ black balls ? Answer is: $$ \frac{ \binom{m}{k - j} \binom{n}{j} } { \binom{m + n}{k} } $$ And since sum of probabilities over $j$ gives 1 we have the Vandermonde identity above. ***First $F_1/F_q$ interpretation (projective geometry)*** **Interpretation:** According to $F_1$-wisdom we should think about the Grassmanian when we see binomial coefficient: $$\binom{n}{k} = \#( Gr(k,n, F_1) ) $$ Hence we might expect some geometric identity related to Grassmannians, and indeed there is motivic identity which is true over any field: $$ [Gr(k,m+n)] = \sum_j [Gr(k-j,m)][Gr(j,n)] [\mathbb{A}^{j(m-k-j)}], $$ As Sasha explained here: https://mathoverflow.net/questions/299581/is-there-a-lift-of-the-q-vandermonde-identity-to-some-geometric-motivic-identi?noredirect=1&lq=1 On the level of $F_q$ points enumeration it gives [$q$-Vandermonde identity][3]. ***Second interpretation (linear algebra)*** I am not sure that this interpretation is fully correct, but let me give it. One of the curious things about $F_1$ is that linear and projective geometry coincide over it. They should be different by $GL(F_q)$ but over $F_1$ it is just $1$ (at least I see like that). **Interpretation:** $$ \binom{n}{k} = \# ( \Lambda^k V^n(F_1)) = dim ( \Lambda^k V^n) $$ I mean that number of elements in vector space coincide with dimension over $F_1$. Now the Vandermonde identity can be interpreted like that: consider $V = V^{m} \oplus V^n$ $$ \Lambda^k V = \oplus_j \Lambda^{k-j} V^m\otimes \Lambda^{j} V^{n} $$ that gives a lift from enumeration to isomorphism of objects (linear spaces) which holds true not only over $F_1$, but actually over any field. ---------------------- Some similar **example** can be found here: https://mathoverflow.net/questions/299748/can-one-divide-algebraic-manifolds-make-sense-gr2-n-gr2-nm-pn-1-p ------------------ As a reincarnation of Gjergji Zaimi's question https://mathoverflow.net/questions/208560/q-catalan-numbers-from-grassmannians?noredirect=1&lq=1 it is natural to ask a particular case of question 1: **Question 2:** Can one give any $\Fun/F_q$ interpretation/lift of any identity related to Catalan numbers ? There are plenty of facts about the [Catalan numbers][4], but it seems not obvious to interpret them geometrically. See comments under above mentioned question - $q$-Catalan number itself is NOT number of points of any smooth projective variety over $F_q$. [1]: https://en.wikipedia.org/wiki/Field_with_one_element [2]: https://en.wikipedia.org/wiki/Vandermonde%27s_identity [3]: https://en.wikipedia.org/wiki/Q-Vandermonde_identity [4]: https://en.wikipedia.org/wiki/Catalan_number