Given a $\sigma$-algebra $\scr F$ on $\Omega$, say that an accuracy scoring rule for $\scr F$ is a function $s$ from the set of all (countably additive) probabilities on $\scr F$ to the $\scr F$-measurable functions on $\Omega$ with values in $[-\infty,M]$ (for some fixed real $M$). A scoring rule $s$ is proper iff $\int_\Omega s(p) \, dp \ge \int_\Omega s(q) \, dp$ for all pairs of probabilities $p$ and $q$, and strictly proper if additionally equality only holds when $p=q$. 

If $\scr F$ is countably generated, it has a strictly proper scoring rule (see my answer [here](https://mathoverflow.net/questions/374094/example-of-a-strictly-proper-scoring-rule-on-a-general-measurable-space)). The same is true for any measure space that has only atomic probability measures, like the one [here](https://www.ams.org/proc/1983-089-04/S0002-9939-1983-0718982-7/S0002-9939-1983-0718982-7.pdf).

Question:

1. Are there any strictly proper scoring rules for a $\scr F$ that is not countably generated and that has a nonatomic probability measure?

2. If yes, is this true for all $\scr F$?

**Note:** The answer to (2) is negative if there are cases where there are more than ${\mathfrak c}^{|\Omega|}$ probability measures on $\scr F$. By a result of [Paris and Koonen][1], it is relatively consistent with the existence of a measurable cardinal that there be a measurable cardinal $\kappa$ that has $2^{2^\kappa}$ normal measures, so it is relatively consistent with the existence of a measurable cardinal that the answer to (2) is negative.

  [1]: https://www.sciencedirect.com/science/article/pii/0003484371900015