First here, $E(f(X(t)|X(0)=x)$ is, not a conditional probability, but a conditional expectation. Second, the event $X(0)=x$ is certain to occur; therefore, conditioning on it does not affect the expectations or probabilities. So, 
$$E(f(X(t)|X(0)=x)=Ef(X(t).$$
Finally, 
$$Ef(X(t))=\sum_{k=0}^\infty\sum_{l=0}^\infty
f\Big(x+\frac{k-l}{\sqrt n}\Big)\frac{(t\lambda)^{k+l}}{k!\,l!}e^{-2t\lambda}.$$